ICSE Class 10 Chemistry 2015 Solved Paper

Complete the following calculations. Show working for complete credit :

Question : 11 of 85

Marks: +1, -0

Calculate the mass of Calcium that will contain the same number of atoms as are present in

3.2 {\gm}

of Sulphur.
[Atomic masses:

S=32, C a=40

]

Solution:

32 {\gm} \;\text " of Sulphur "\;\;=1 {\mole}

∴ \;\; 3.2 {\gm} \;\text " of Sulphur "\;\;=\;{1}/{32} × 3.2

\;=0.1 {\moles}

At. Mass of Calcium

=40

∴

mass of 0.1 mole of

{\Ca}

=40 \×0.1=4 \ {\gm}

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