CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

Question : 7 of 13

Marks: +1, -0

A ray of light travels a distance of

12.0 {\m}

in a transparent sheet in

60 {\ns}

. The refractive index of the sheet is

Solution:

Speed of light in the sheet

\;=\;{12 {\m}}/{60 × 10^{-9} {\ s}}

\;=2 × 10^8 {\ms}^{-1}

Speed of light in vacuum

=3 × 10^8 {\ms}^{-1}

So, the refractive index of the sheet

=\;{3 × 10^8}/{2 × 10^8}=1.5

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