CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

Question : 4 of 13

Marks: +1, -0

The radius of

{ }_{13}^{27} X

nucleus is

R

. The radius of

{ }_{53}^{125} Y

nucleus will be

Solution:

R=R_0 A^{1 \/ 3}

\;\text " For X, "\;\;R=R_0(27)^{1 \/ 3}

\;\text " Or, "\;\;R=3 R_0

∴ \;R_0=\;{R}/{3}

\;\text " For Y, "\;\;R^{'}=R_0(125)^{1 \/ 3}

\;\text " Or, "\;\;R^{'}=5 R_0

∴ \;R^{'}=\;{5 R}/{3}

Go to Question:

Prev Question

Next Question