CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

Question : 1 of 13

Marks: +1, -0

SECTION - A

The energy of a photon of wavelength

663 {\nm}

Solution:

E\;=\;{h c}/{λ}

\;=\;{6.6 × 10^{-34} × 3 × 10^8}/{663 × 10^{-9}}

\;=2.98 × 10^{-19} {\J}

\;\; ≈ 3.0 × 10^{-19} {\J}

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