CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

Question : 4 of 13

Marks: +1, -0

A steady current of

8 {\mA}

flows through a wire. The number of electrons passing through a cross-section of the wire in

10 {\ s}

Solution:

\;\;n=\;{I t}/{e}

\;\text " Or, "\;\;n=\;{8 × 10^{-3} × 10}/{1.6 × 10^{-19}}

∴ \;n=5 × 10^{17}

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