CBSE Class 12 Physics 2023 Delhi Set 1 Paper

Question : 4 of 35

Marks: +1, -0

A square shaped coil of side

10 {\cm}

, having 100 turns is placed perpendicular to a magnetic field which is increasing at

1 {\T} \/ {\ s}

. The induced emf in the coil is

Solution:

N\;=100

A\;=\;{1}/{10} × \;{1}/{10} {\m}^2

\;{d {\B}}/{d t}\;=1.0 {\Ts}^{-1}

\;\text " emf "\;\;= {\NA} \;{d {\B}}/{d t}

∴

\;\text " emf "\;\;=100 × \;{1}/{10} × \;{1}/{10} × 1

\;=1 {\V}

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