CBSE Class 12 Physics 2022 Term 2 Outside Delhi Set 1 Solved ...

CBSE Class 12 Physics 2022 Term 2 Outside Delhi Set 1 Solved Paper

Question : 9 of 12

Marks: +1, -0

An electron is accelerated from rest through a potential difference of

100 {\V}

.
Find:
(i) the wavelength associated with
(ii) the momentum and
(iii) the velocity required by the electron. 3

Solution:

(i) Wavelength

= λ = h/√{2meV}

∴ λ= {6.6×10^{-34}}/√{2×9.1×10^{31}×1.6×10^{-19}×100}

=1.2×10^{-10}m = 1.2 Å

(ii) Momentum

= p=h/λ

∴ p = {6.6×10^{-34}}/{1.2×10^{-10}}

=5.5 ×10^{-24} kg m\/s

(iii) Momentum = p=mv

∴

Velocity

= v=p/m

= 5.5×10^{-24}/9.1×10^{-31}

= 6×10^6 m\/s

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