CBSE Class 12 Physics 2019 Outside Delhi Set 1 Paper

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Question : 7 of 27
 
Marks: +1, -0
A photon and a proton have the same de-Broglie wavelength λ . Prove that the energy of the photon is (2mλc∕h) times the kinetic energy of the proton.
Solution:
For writing expression for energy of photon
For writing expression for kinetic energy of proton
For proving the relationship between the two
Energy of photon, Ep=hcλ
For proton, λ=hmv
mv=hλ
Kinetic energy of proton,
Ek=12mv2
Ek=12h2mλ2
Ep=(2mλch)Ek
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