CBSE Class 12 Physics 2018 Delhi Set 1 Paper

Question : 6 of 26

Marks: +1, -0

SECTION -B

Two electric bulbs

P

and

Q

have their resistances in the ratio of

1: 2

. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs.

Solution:

Formula

\;\text " Stating that currents are equal "

\;\text " Ratio of powers "

\;\text " Power "\;=R^2 R

The current, in the two bulbs, is the same as they are connected in series.

∴ \;\; \;{P_1}/{P_2}\;=\;{I^2 R_1}/{I^2 R_2}=\;{R_1}/{R_2}

\;=\;{1}/{2}

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