CBSE Class 12 Physics 2018 Delhi Set 1 Paper

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Question : 14 of 26
 
Marks: +1, -0
(a) An iron ring of relative permeability µr has windings of insulated copper wire of n turns per metre. When the current in the windings is I, find the expression for the magnetic field in the ring.
(b) The susceptibility of a magnetic material is 0.9853 . Identify the type of magnetic material. Draw the modification of the field pattern on keeping a piece of this material in a uniform magnetic field.
Solution:
(a) Expression for Ampere's circuital law
Derivation of magnetic field inside the ring
(b) Identification of the material
Drawing the modification of the field pattern
(a)From Ampere's circuital law, we have,
∮B→dl→=µ0µrIendosed ......(i)
For the field inside the ring, we can write
∮B→dl→=∮B→dl→=B.2πr(r= radius of the ring )
Also, Ienclosed =(2Ï€rn)I using equation (i)
∴B.2πr=µ0µr⋅(n.2πr)I
∴B=µ0µrnI
(b) The material is paramagnetic. The field pattern gets modified as shown in the figure below.
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