CBSE Class 12 Physics 2017 Delhi Set 3 Paper

Question : 3 of 8

Marks: +1, -0

α

-particle and a proton are accelerated through the same potential difference. Find the ratio of their de Broglie wavelengths.

Solution:

Finding the ratio of de Broglie wavelength

(\;{λ α}/{λ p})

λ=\;{h}/{p}=\;{h}/{{√{2 m K}}}=\;{h}/{{√{2 m q V}}}

∴ \;{λ α}/{λ p}=\;{h}/{{√{2 m_α q_α V}}} × \;{{√{2 m_p q_p V}}}/{h}

\;{λ_α}/{λ_p}\;=\;{{√{m_p q_p}}}/{{√{m_α q_α}}}

\;=\;{{√{m_p q_p}}}/{{√{4 m_p 2 q_p}}}

\;=\;{1}/{2 {√{2}}}

λ_α: λ_p\;=1: 2 {√{2}}

Go to Question:

Prev Question

Next Question