Calculation of collector current ${\mathit{I}}_{\mathit{e}}$ base current ${\mathit{I}}_{\mathit{B}}$ and input signal voltage ${\mathit{V}}_{\mathit{i}}$
Given ${\mathit{R}}_{\mathit{e}}=2\mathrm{k}\mathit{\Omega }$
$=2\times {10}^3\mathit{\Omega }$
${\mathit{V}}_{\mathit{C}\mathit{E}}={\mathit{I}}_{\mathit{C}}{\mathit{R}}_{\mathit{C}}$
${\mathit{I}}_{\mathit{C}}=\frac{{\mathit{V}}_{\mathit{C}\mathit{E}}}{{\mathit{R}}_{\mathit{C}}}=\frac{2}{2\times {10}^3}\mathit{A}$
$={10}^{-3}\mathrm{A}$
$=1\mathrm{mA}$

$\therefore 100=\frac{{10}^{-3}}{{\mathit{I}}_{\mathit{B}}}$
$\therefore {\mathit{I}}_{\mathit{B}}={10}^{-5}\mathrm{A}$
Input signal voltage
${\mathit{V}}_{\mathit{i}}={\mathit{I}}_{\mathit{B}}{\mathit{R}}_{\mathit{B}}$
$=1\times {10}^{-5}\times {10}^3\mathit{\Omega }$
$={10}^{-2}\mathit{V}$
[Note : Give full credit if student calculates the required quantities by any other alternative method]