CBSE Class 12 Physics 2017 Delhi Set 1 Paper

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Question : 19 of 26
 
Marks: +1, -0
(i) A radioactive nucleus ' A ' undergoes a series of decays as given below:
A──▸αA1──▸βA2──▸αA3──▸γA4
The mass number and atomic number of A2 are 176 and 71 respectively.
Determine the mass and atomic numbers of A4 and A.
(ii) Write the basic nuclear processes underlying β+and β−decays.
Solution:
(i) Determining the mass and atomic number of A4 and A
(ii) Basic nuclear processes of β+and β−decays
(i) A4: Mass Number : 172

Atomic Number : 69
A : Mass Number : 180
Atomic Number : 72
[Alternatively : Give full credit if student considers decay and find atomic and mass numbers accordingly
72180A──▸α70176A1──▸β+71176A2──▸α 69172A3──▸γ69172A4
Gives the values quoted above.
If the student takes β+decay
72180A──▸α70176A1──▸β+71176A2──▸α 69172A3──▸γ69172A4
This would give the answers: (A4:172,69);(A:180,74)]
(ii) Basic nuclear process for β+decay p→n+10e +v
For β−decay n→p+−10e+v
[Note: Give full credit of this part, if student writes the processes as conversion of proton into neutron for decay and neutron into proton for decay.]
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