CBSE Class 12 Physics 2016 Outside Delhi Set 1 Paper

Question : 8 of 26

Marks: +1, -0

Calculate the de-Broglie wavelength of the electron orbiting in the

n=2

state of hydrogen atom.

Solution:

Formulae of kinetic energy and de-Broglie a wavelength
Calculation and Result
Kinetic Energy for the second state-

E_k=\;{13.6 e {\V}}/{n^2}=\;{13.6 {\eV}}/{4}

=3.4 × 1.6 × 10-19 {\J}

\;\;\text " de-Broglies wavelength "\; λ=\;{h}/{{√{2 m E_k}}}

\;=\;{6.63 × 10^{-34}}/{√{2 × 9.1 × 10^{-31} × 3.4 × 1.6 × 10^{-19}}}

\;=0.067 {\nm}

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