CBSE Class 12 Physics 2014 Delhi Set 2 Paper

Question : 3 of 8

Marks: +1, -0

An electric dipole of length

2 {\cm}

, when placed with its axis making an angle of

60^{∘}

with a uniform electric field, experiences a torque of

8 {√{3}} {\Nm}

. Calculate the potential energy of the dipole, if it has a charge of

± 4 {\nC}

Solution:

τ\;=p E sin \;θ

8 {√{3}}\;=p E sin \;θ

p E \;{{√{3}}}/{2}\;=8 {√{3}}

So,

p E=16

Potential energy of the dipole

\;=-p E \cos θ

U\;=-p E \cos 60

U\;=-16 × 0.5

U\;=-8 {\J}

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