CBSE Class 12 Physics 2014 Delhi Set 1 Paper

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Question : 18 of 30
 
Marks: +1, -0
(i) Monochromatic light of frequency 6.0×1014Hz is produced by a laser. The power emitted is 2.0× 10−3W. Estimate the number of photons emitted per second on an average by the source.
(ii) Draw a plot showing the variation of photoelectric current versus the intensity of incident radiation on a given photosensitive surface.
Solution:
(i) An energy,
E=hv
=6.63×10−34×6.05×1014
=3.98×10−19J
Now,number of photons emitted per second
n=pE=2.0×10−33.98×10−19J
=5×1015 photons per second
(ii)
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