CBSE Class 12 Physics 2014 Delhi Set 1 Paper

Question : 16 of 30

Marks: +1, -0

An electric dipole of length

4 {\cm}

, when placed with its axis making an angle of

60^{∘}

with a uniform electric field, experiences a torque of

4 {√{3}} {\Nm}

. Calculate the potential energy of the dipole, if its has charge

± 8 {\nC}

Solution:

τ\;=p E sin \;θ

4 {√{3}}\;=p E sin \;θ

p E \;{{√{3}}}/{2}\;=4 {√{3}}

So,

\;\; p E=8

Potential energy of the dipole

=-p E \cos θ

\;U=-p E \cos 60

\;U=-8 × 0.5

\;U=-4 J

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