Recent studies suggest that roughly $12\%$ of the world population is left handed.
Depending upon the parents, the chances of having a left handed child are as follows :
A : When both father and mother are left handed :
Chances of left handed child is $24\%$.
B : When father is right handed and mother is left handed :
Chances of left handed child is $22\%$.
C : When father is left handed and mother is right handed :
Chances of left handed child is $17\%$.
D : When both father and mother are right handed :
Chances of left handed child is 9\%.
Assuming that $\mathrm{P}\left(\mathrm{A}\right)=\mathrm{P}\left(\mathrm{B}\right)=\mathrm{P}\left(\mathrm{C}\right)=\mathrm{P}\left(\mathrm{D}\right)=\frac{1}{4}$ and $\mathrm{L}$ denotes the event that child is left handed.
Based on the above information, answer the following questions :
(i) Find $\mathrm{P}\left(\mathrm{L}∕\mathrm{C}\right)$
(ii) Find $\mathrm{P}\left(\overline{\mathrm{L}}∕\mathrm{A}\right)$
(iii) (a) Find $\mathrm{P}\left(\mathrm{A}∕\mathrm{L}\right)$
OR
(b) Find the probability that a randomly selected child is left handed given that exactly one of the parents is left handed.