(a) Find the coordinates of the foot of the perpendicular drawn from point (5,7,3) to the line \frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}. OR (b) If \overrightarrow{a}=\stackrel{\^}{i}+\stackrel{\^}{j}+\stackrel{\^}{k} and \overrightarrow{b}=\stackrel{\^}{i}+2 \stackrel{\^}{j}+3 \stackrel{\^}{k} then find a unit vector perpendicular to both \overrightarrow{a}+\overrightarrow{b} and \overrightarrow{a}-\overrightarrow{b}.

CBSE Class 12 Math 2023 Delhi Set 3 Solved Paper - Question 11

Question : 11 of 12

Marks: +1, -0

(a) Find the coordinates of the foot of the perpendicular drawn from point

(5,7,3)

to the line

\;{x-15}/{3}=\;{y-29}/{8}=\;{z-5}/{-5}

.
OR
(b) If

{a}↖{→}={i}↖{\^}+{j}↖{\^}+{k}↖{\^}

and

{b}↖{→}={i}↖{\^}+2 {j}↖{\^}+3 {k}↖{\^}

then find a unit vector perpendicular to both

{a}↖{→}+{b}↖{→}

and

{a}↖{→}-{b}↖{→}

Solution:

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