\sin [\frac{\pi}{3}+ \sin ^{-1} (\frac{1}{2}) ] is equal to:

CBSE Class 12 Math 2023 Delhi Set 1 Solved Paper - Question 2

Question : 2 of 38

Marks: +1, -0

sin \; [\;{π}/{3}+ sin \;^{-1} (\;{1}/{2}) ]

is equal to:

Solution:

\;\text " Explanation: "\; sin \; [\;{π}/{3}+ sin \;^{-1} (\;{1}/{2}) ]

\;\;\;\; sin \; (\;{π}/{3}+\;{π}/{6}) = sin \;\;{π}/{2}=1

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