If \overrightarrow{a}=\stackrel{\^}{i}+\stackrel{\^}{j}+\stackrel{\^}{k}, \overrightarrow{a} \cdot \overrightarrow{b}=1 and \overrightarrow{a} \times \overrightarrow{b}=\stackrel{\^}{j}-\stackrel{\^}{k}, then find |\overrightarrow{b}|

CBSE Class 12 Math 2022 (Term II) Delhi Set 1 Solved Paper

Question : 4 of 14

Marks: +1, -0

{a}↖{→}={i}↖{\^}+{j}↖{\^}+{k}↖{\^}, {a}↖{→} ⋅ {b}↖{→}=1

and

{a}↖{→} × {b}↖{→}={j}↖{\^}-{k}↖{\^}

, then find

|{b}↖{→}|

Solution:

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