CBSE Class 12 Math 2022 Term I Solved Paper

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Section C
Attempt any 8 questions out of the Questions 41-50. Each question is of one mark.
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Question : 41 of 50
 
Marks: +1, -0
In a sphere of radius r, a right circular cone of height h having maximum curved surface area is inscribed. The expression for the square of curved surface of cone is
Solution:
Here, CSA of cone =Ï€Rl
Radius of sphere =r
height of cone =h
In â–³AOC ,
AO2=AC2+OC2
⇒r2=R2+(h−r)2
⇒R2=2hr−h2
∴ Radius of cone, R=2hr−h2⋅⋅⋅⋅⋅⋅⋅(i)
In â–³ABC ,
AB2=AC2+BC2
⇒l2=R2+h2
⇒l2=2hr−h2+h2
∴ slant height =2hr⋅⋅⋅⋅⋅⋅⋅(ii)
CSA of cone =Ï€Rl
=π2hr−h22hr
( CSA of cone )2=π2(2hr−h2)(2hr)
=2π2hr(2hr−h2)
=2π2r(2rh2−h3)
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