CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 32 of 50
 
Marks: +1, -0
If for the matrix A=[α−2−2α], |A3∣=125, then the value of α is
Solution:
Given, A=[α−2−2α]
⇒|A|=α2−4⋅⋅⋅⋅⋅⋅⋅(i)
Also, given |A3|=125
⇒|A|3=125
⇒|A|=5
⇒α2−4=5 [from eq. (i)]
⇒α2=9
⇒α=±3
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