CBSE Class 12 Math 2022 Term I Solved Paper - Question 28 | ...

CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 28 of 50

Marks: +1, -0

The corner points of the feasible region for a Linear Programming problem are

P(0,5), Q(1,5), R(4,2)

and

S(12,0)

. The minimum value of the objective function

Z=2 x+5 y

is at the point

${\P}$
Q
${\R}$
${\S}$

Solution:

Corner Points	Value of $Z=2 x+5 y$
$P(0,5)$	$Z=2(0)+5(5)=25$
$Q(1,5)$	$Z=2(1)+5(5)=27$
$R(4,2)$	$Z=2(4)+5(2)=18$ Minimum
$S(12,0)$	$Z=2(12)+5(0)=24$

Thus, minimum value of

Z

occurs at

R(4,2)

.

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