The principal value of \tan ^{-1} (\tan \frac{9 \pi}{8}) is

CBSE Class 12 Math 2022 Term I Solved Paper - Question 19

Question : 19 of 50

Marks: +1, -0

The principal value of

\tan ^{-1} (\tan \;{9 π}/{8})

Solution:

Explanation:

\tan ^{-1} (\tan \;{9 π}/{8}) =\tan ^{-1} (\tan (π+\;{π}/{8}) )

=\tan ^{-1} (\tan \;{π}/{8}) =\;{π}/{8} \;\; [ ∵ \;{π}/{8} ∈ (\;{-π}/{2}, \;{π}/{2}) ]

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