If \overrightarrow{a} \cdot \overrightarrow{b}=\frac{1}{2}|\overrightarrow{a}|| \overrightarrow{b}|, then the angle between \overrightarrow{a} and \overrightarrow{b} is

CBSE Class 12 Math 2020 Outside Delhi Set 1 Solved Paper

Question : 5 of 36

Marks: +1, -0

{a}↖{→} ⋅ {b}↖{→}=\;{1}/{2}|{a}↖{→}|| {b}↖{→}|

, then the angle between

{a}↖{→}

and

{b}↖{→}

Solution:

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