The lines \frac{x-2}{1}=\frac{ {\y}-3}{1}= {4- {\z}}/{ {\k}} and \frac{x-1}{ {\k}}=\frac{ {\y}-4}{2}=\frac{ {\z}-5}{-2} are mutually perpendicular if the value of {\k} is

CBSE Class 12 Math 2020 Delhi Set 1 Solved Paper - Question 7

Question : 7 of 36

Marks: +1, -0

The lines

\;{x-2}/{1}=\;{ {\y}-3}/{1}=\;{4- {\z}}/{ {\k}}

and

\;{x-1}/{ {\k}}=\;{ {\y}-4}/{2}=\;{ {\z}-5}/{-2}

are mutually perpendicular if the value of

{\k}

Solution:

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