CBSE Class 12 Math 2020 Delhi Set 1 Solved Paper

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Question : 3 of 36
 
Marks: +1, -0
If y=Ae5x+Be−5x, then d2ydx2 is equal to
Solution:
Given:
y=Ae5x+Be−5x
∴dydx=5Ae5x−5Be−5x
⇒d2ydx2=25Ae5x+25Be−5x
⇒d2ydx2=25y.
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