Let \overrightarrow{a}, \overrightarrow{b} and \overrightarrow{c} be three vectors such that |\overrightarrow{a}|=1,|\overrightarrow{b}|=2 and |\overrightarrow{c}|=3. If the projection of \overrightarrow{b} along \overrightarrow{a} is equal to the projection of \overrightarrow{c} along \overrightarrow{a}; and \overrightarrow{b}, \overrightarrow{c} are perpendicular to each other, then find |3 \overrightarrow{a}-2 \overrightarrow{b}+2 \overrightarrow{c}|

CBSE Class 12 Math 2019 All India Set 1 Solved Paper

Question : 22 of 29

Marks: +1, -0

Let

{a}↖{→}, {b}↖{→}

and

{c}↖{→}

be three vectors such that

|{a}↖{→}|=1,|{b}↖{→}|=2

and

|{c}↖{→}|=3

. If the projection of

{b}↖{→}

along

{a}↖{→}

is equal to the projection of

{c}↖{→}

along

{a}↖{→}

; and

{b}↖{→}, {c}↖{→}

are perpendicular to each other, then find

|3 {a}↖{→}-2 {b}↖{→}+2 {c}↖{→}|

Solution:

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