CBSE Class 12 Math 2018 Solved Paper

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Question : 6 of 29
 
Marks: +1, -0
Given A = [2−3−47], compute A−1 and show that 2 A−1 = 9I - A
Solution:
Given A = [2−3−47]
|A| = 2 × - [(- 4) × (- 3)] = 2 ⇒ A−1 exist.
Cofactors of matrix A are
C11 = 7 , C12 = - 4 , C21 = - 3 , C22 = 2
Minors of matrix A are
M11 = (−1)1+1 × 7 = 7
M12 = (−1)1+2 × (- 4) = 4
M21 = (−1)3+1 × (- 3) = 3
M22 = (−1)2+2 × 2 = 2
A−1 = 12(7342)
2 A−1 = (7342) ... (i)
9I - A = 9 (1001)−(2−3−47)
= (7342) ... (ii)
⇒ 2X−1 = 9I - A from (i) and (ii)
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