CBSE Class 12 Math 2018 Solved Paper - Question 1 | ExamSiri

CBSE Class 12 Math 2018 Solved Paper

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Question : 1 of 29

Marks: +1, -0

Find the value of

tan^{-1} √3 - cot^{-1}(-√3)

Solution:

tan^{-1} √3 - cot^{-1}(-√3)

=

tan^{-1} √3 - [π - cot^{-1}(-√3)

] (Since

cot^{-1}

(- x) = π -

cot^{-1}

(x))
=

tan^{-1} √3 - π + cot^{-1}(-√3)

tan^{-1} √3 + cot^{-1}(-√3)

- π
=

π/2 - π

(Since

tan^{-1}

(x) +

cot^{-1}

(x) =

π/2

)
= -

π/2

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