CBSE Class 12 Math 2013 Solved Paper

© examsiri.com
Question : 19 of 29
 
Marks: +1, -0
Evaluate: ∫04 |x| + |x - 2| + |x - 4| dx
Solution:
∫04 |x| + |x - 2| + |x - 4| dx
= ∫02 f (x) dx + ∫24 f (x) dx
= ∫02 x - x + 2 - x + 4 dx + ∫24 x + x - 2 - x + 4 dx
= ∫02 6 - x dx + ∫24 x + 2 dx
= |6x−x22|02 + |x22+2x|04
= 12 - 2 + 8 + 8 - 2 - 4 = 20
© examsiri.com
Go to Question: