CBSE Class 12 Math 2012 Solved Paper

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Question : 14 of 29
 
Marks: +1, -0
If (cosx)y = (cosy)x , find dydx
OR
If sin y = x sin (a + y), prove that dydx = sin2a+ysina
Solution:
The given function is (cosx)y = (cosy)x
Taking logarithm on both the sides, we obtain
ylog cosx = xlog cosy
Differentiating both sides, we obtain
log cosx × dydx + y × ddx (log cos x) = log cos y × ddx (x) + x × ddx (log cos y)
⇒ log cos x × dydx + y × 1cosx × ddx (cos x) = log cos y × 1 + x × 1cosy × ddx (cos y)
⇒ log cos x × dydx + ycosx (- sin x) = log cos y + xcosy × (- sin y) × dydx
⇒ log cos x × dydx - y tan x - log cos y - x tan y × dydx
⇒ log cos x × dydx + x tan y × dydx = log cos y + y tan x
⇒ (log cos x + x tan y) × dydx = log cos y + y tan x
∴ dydx = logcosy+ytanxlogcosx+xtany
OR
We have,
siny = x sin (a + y)
⇒ x = sinysin(a+y)
Differentiating the above function we have,
1 =
sin(a+y)×cosydydx−siny×cos(a+y)dydxsin2(a+y)

⇒ sin2 (a + y) = [sin (a + y) × cos y - sin y cos (a + y)] dydx
⇒
sin2(a+y)[sin(a+y)×cosy−sinycos(a+y)]
= dydx
⇒ sin2(a+y)sin(a+y−y) = dydx
⇒ sin2(a+y)sina = dydx
⇒ dydx = sin2(a+y)sina
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