2x + y – z = 5
Dividing both sides by 5,
$\frac{2\mathit{x}}{5}+\frac{\mathit{y}}{5}-\frac{\mathit{z}}{5}$ = 1
⇒ $\frac{\mathit{x}}{\frac{5}{2}}+\frac{\mathit{y}}{5}+\frac{\mathit{z}}{-5}$ = 1
It is known that the equation of a plane in intercept form is $\frac{\mathit{x}}{\mathit{a}}+\frac{\mathit{y}}{\mathit{b}}+\frac{\mathit{z}}{\mathit{c}}$ = 1, where a, b and c are the intercepts cut off by the plane at x, y, and z-axes respectively. Thus, the intercept cut off by the given plane on the x-axis is $\frac{5}{2}$