CBSE Class 12 Math 2009 Solved Paper

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Question : 3 of 29
 
Marks: +1, -0
If ∫01(3x2+2x+k) dx = 0 , find the value of k.
Solution:
Given: ∫01(3x2+2x+k) dx =
⇒ [3x33+2x22+kx]01 = 0
⇒ [x3+x2+kx]01 = 0
⇒ [1 + 1 + k] = 0
⇒ k = - 2
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