CBSE Class 12 Math 2008 Solved Paper

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Question : 6 of 29
 
Marks: +1, -0
Evaluate: ∫ x21+x3 dx
Solution:
x21+x3 dx
Let 1 + x3 = t
⇒ 0 + 3x2dx = dt
x2dx = dt3
∴ ∫ (x21+x3) dx = ∫ dt3t
= 13dtt
= 13 log |t| + c
= 13 log |1+x3| + c
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