CBSE Class 12 Math 2008 Solved Paper

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Question : 2 of 29
 
Marks: +1, -0
Evaluate: sin [π3−sin−1(12)]
Solution:
We know that the domain and range of the principal value branch of function sin−1 is defined as:
sin−1 " [- 1 , 1] → [−π2,π2]
∴ sin [π3−sin−1(−12)] = sin [π3−(−π6)]
= sin [Ï€3+Ï€6]
= sin [Ï€2]
= 1
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