(a) Molar conductivity
${\mathrm{\Lambda }}_{\mathit{m}}=\mathrm{}\mathit{\kappa }\times 1000\mathit{C}$ $=\frac{8\times {10}^{-5}\mathrm{}\mathit{S}\mathrm{}{\mathit{c}\mathit{m}}^{-1}\times 1000}{2\times {10}^{-3}\mathrm{}\mathit{m}\mathit{o}\mathit{l}\mathrm{}{\mathit{L}}^{-1}}$
$=\frac{8\times {10}^{-2}}{2\times {10}^{-3}}=40\mathrm{}\mathit{S}\mathrm{}{\mathit{c}\mathit{m}}^2\mathrm{}{\mathit{m}\mathit{o}\mathit{l}}^{-1}$
Degree of dissociation
$\frac{{\mathrm{\Lambda }}_{\mathit{m}}}{\mathrm{\Lambda }{°}_{\mathit{m}}}=\frac{40}{404}=0.099$
(b) $\mathit{N}\mathit{i}\mathit{─}\mathit{─}\mathit{─}\mathit{─}▸{\mathit{N}\mathit{i}}^{2+}\left({\mathit{E}}_0=-0.25\mathit{V}\right)$ ( Oxidation half)
$2{\mathit{A}\mathit{g}}^{+}\mathit{─}\mathit{─}\mathit{─}\mathit{─}▸2\mathit{A}\mathit{g}\left({\mathit{E}}_0=0.80\mathit{V}\right)$ (Reduction half)
$\mathit{E}°={\mathit{E}}_{\mathit{c}}-{\mathit{E}}_{\mathit{a}}$ $=0.80-\left(-0.25\right)=1.05\mathit{V}$
$\mathrm{\Delta }\mathit{G}=\mathit{n}\mathit{F}\mathit{E}°$
$=2\times 96500\times 10.5$
$=202.650\mathrm{}\mathit{J}\mathrm{}{\mathit{m}\mathit{o}\mathit{l}}^{-1}$
$=202.650\mathrm{}\mathit{k}\mathit{J}\mathrm{}{\mathit{m}\mathit{o}\mathit{l}}^{-1}\mathrm{}$

$\log {\mathit{K}}_{\mathit{c}}=\frac{1.05\times 2}{0.0591}=35.53$
By taking Antilog
Antilog 35.35
$={10}^{53}\times 3.38$