A voltaic cell is made by connecting two half cells represented by half equations below: {Sn}_{({aq})}^{2+}+2 {e}^{-} \\to{Sn}_{({s})} {E}^\circ =-0.14 {V} {Fe}^{3+}{ }_{(\text{aq })}+{e}^{-} \\to{Fe}_{(\text{aq })}^{2+} {E}^\circ =+0.77 {V}

Correct Answer is : Sn is oxidised and the voltage of the cell is 0.91V

{\Fe}^{2+} is oxidised and the voltage of the cell is -0.91 {\V}

{\Sn} is oxidised and the voltage of the cell is 0.91 {\V}

{\Fe}^{2+} is oxidised and the voltage of the cell is 0.91 {\V}

{\Sn} is oxidised and the voltage of the cell is 0.63 {\V}

CBSE Class 12 Chemistry 2023 Delhi Set 1 Solved Paper

Question : 3 of 35

Marks: +1, -0

A voltaic cell is made by connecting two half cells represented by half equations below:

{Sn}_{({aq})}^{2+}+2 {e}^{-} \→{Sn}_{({s})} {E}°

=-0.14 {V}

{Fe}^{3+}{ }_{(\text "aq ")}+{e}^{-} \→{Fe}_{(\text "aq ")}^{2+} {E}°

=+0.77 {V}

Solution:

Explanation:

{Sn}

is oxidized as it is having -ve value of electrode potential.

E°=E_c-E_a

=0.77(-0.14)

=0.91 V

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