CBSE Class 12 Chemistry 2022 Term 2 Delhi Set 1
© examsiri.com
Question : 7 of 12
Marks:
+1,
-0
(a) Write any two consequences of Lanthanoid Contraction.
(b) Name the element of series which exhibits the largest number of oxidation states. Give reason.
(b) Name the element of series which exhibits the largest number of oxidation states. Give reason.
Solution:
(a) The two consequences of lanthanide contraction are:
(i) Due to close similarity in electronic configuration and ionic radii, the lanthanides have identical chemical properties which makes their separation difficult.
(ii) Due to lanthanide contraction, the size of ions decrease regularly with increase in atomic number. According to Fajan's rule, decrease in size of ions increase the covalent character and decrease the basic character between and ion in . Since the order of size of ions are .
(b) The element which shows largest number of oxidation states in series is Manganese (Mn). It shows the following oxidation states , and +7 . It is because it contains the maximum no. of unpaired in the outermost shell, i.e., .
(i) Due to close similarity in electronic configuration and ionic radii, the lanthanides have identical chemical properties which makes their separation difficult.
(ii) Due to lanthanide contraction, the size of ions decrease regularly with increase in atomic number. According to Fajan's rule, decrease in size of ions increase the covalent character and decrease the basic character between and ion in . Since the order of size of ions are .
(b) The element which shows largest number of oxidation states in series is Manganese (Mn). It shows the following oxidation states , and +7 . It is because it contains the maximum no. of unpaired in the outermost shell, i.e., .
© examsiri.com
Go to Question: