CBSE Class 12 Chemistry 2022 Term 1 Paper

Question : 26 of 55

Marks: +1, -0

SECTION - B

An unknown gas '

X

' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of '

X

' gas when the pressure of gas is doubled at the same temperature i

Solution:

Mole fraction of gas

{\X}

in solution

=0.04

Pressure

=2.5

bar
Let

{\p}_1\;= {\P}_0 {\X}_1

2.5\;=0.04 {\P}_0

......(i)
Let pressure be doubled, then

p_2

5.0= {\X}_2 {\P}_0

......(ii)
Dividing Eqn ii by eqn

{\I}

, we get

5.0 \/ 2.5\;=X_2 \/ 0.04

2 × 0.04\;=X_2

X_2\;=0.08

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