CBSE Class 12 Chemistry 2020 Outside Delhi Set 1 Solved Paper

Question : 27 of 37

Marks: +1, -0

State Henry's law. Calculate the solubility of

{\CO}_2

in water at

298 {\K}

under

760 {\mm} {\Hg}

.
(

{\K}_{ {\H}}

for

{\CO}_2

in water at

298 {\K}

1.25 × 10^6 {\mm} {\Hg}

)

Solution:

Henry's law: The mass of a gas dissolved in a given volume of the liquid at a constant temperature depends upon the pressure which is applied.

{\K}_{ {\H}} \;\text " for "\; {\CO}_2=1.25 × 10^6 {\mm} {\Hg}\;

x_{ {\CO}_2}\;=\;{\;\text " Partial pressure of "\; {\CO}_2}/{ {\K}_{ {\H}} \;\text " for "\; {\CO}_2}

=\;{760 {\mm} {\Hg}}/{1.25 × 10^6 {\mm} {\Hg} .}

\;=608 × 10^{-6}

Mole fraction represents the solubility of

{\CO}_2

in water.

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