• ${\mathrm{PbO}}_2$ is reduced to ${\mathrm{PbSO}}_4$ at the cathode.
  
• $\mathrm{Pb}$ is oxidised to ${\mathrm{PbSO}}_4$ at the anode.
  
• Both electrodes are immersed in the same aqueous solution of ${\mathrm{H}}_2{\mathrm{SO}}_4$.
  
• All the above are true.