CBSE Class 12 Chemistry 2019 Delhi Set 3 Solved Paper
© examsiri.com
Question : 5 of 9
Marks:
+1,
-0
Write the hybridization and magnetic character of the following complexes:
(i)
(ii)
(i)
(ii)
Solution:
(i) In the oxidation state of is +2 . The outermost electronic configuration of is . HO is weak field ligand and does not cause pairing up of electrons.
In this complex, there are 4 unpaired electrons. Therefore, it involves hybridisation and is paramagnetic.
(ii) In , the oxidation state of is zero. The outermost electronic configuration of is . CO is strong field ligand, causes pairing up of -electrons into the -orbitals.
Therefore, it involves dsp hybridisation and is diamagnetic.
In this complex, there are 4 unpaired electrons. Therefore, it involves hybridisation and is paramagnetic.
(ii) In , the oxidation state of is zero. The outermost electronic configuration of is . CO is strong field ligand, causes pairing up of -electrons into the -orbitals.
In this complex, there is no unpaired electron.
Therefore, it involves dsp hybridisation and is diamagnetic.
© examsiri.com
Go to Question: