CBSE Class 12 Chemistry 2018 Solved Paper

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Question : 7 of 26
 
Marks: +1, -0
For the reaction
2N2O5(g)→4NO2(g)+O2(g),
the rate of formation of NO2(g) is 2.8×10−3M s−1.
Calculate the rate of disappearance of N2O5(g)
Solution:
Rate =14∆NO2∆(t)=12∆(N2O5)∆(t)
14(2.8×10−3)=−12∆(N2O5)∆(t)
Rate of disappearance of N2O5 (−∆N2O5∆(t))1.4×10−3M∕ s
(Deduct half mark if unit is wrong or not written)
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