CBSE Class 12 Chemistry 2018 Solved Paper

Question : 22 of 26

Marks: +1, -0

(a) Write the formula of the following co-ordination compound :
Iron(III) hexacyanoferrate(II)
(b) What type of isomerism is exhibited by the complex

[ {\Co} ( {\NH}_3) _5 {\Cl}] {\SO}_4

?
(c) Write the hybridisation and number of unpaired electrons in the complex

[ {\CoF}_6] ^{3-}

(

Atomic No. of

{\Co}=27

)

Solution:

(a)

{\Fe}_4 [ {\Fe}( {\CN})_6] _3

(b) Ionization isomerism.

[ {\Co} ( {\NH}_3) _5 {\SO}_4] {\Cl} \;\text " and "\; [ {\Co} ( {\NH}_3) _5 {\Cl}] {\SO}_4

(c)

[ {\COF}_6] ^{3-}

In this complex, Co possesses +3 oxidation state.

{\Co}^{3+}=3 d^6

Since

{\F}^{-}

is weak ligand so it cannot push the electrons to pair up and it forms outer orbital high spin complex.

Number of unpaired electrons

=4

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