CBSE Class 12 Chemistry 2016 Outside Delhi Set 1 Solved Paper

© examsiri.com
Question : 12 of 26
 
Marks: +1, -0
For the first order thermal decomposition reaction, the following data were obtained :
C2H5Cl(g)→C2H4(g)+HCl(g)
Time∕secTotalpressure∕atm00.303000.50
Calculate the rate constant
(Given : log2=0.3010,log3=0.4771, log4=0.6021)
Solution:
Given : Initial pressure,
P0=0.30atm
Pt=0.50atm
t=300 s
Rate constant, k=2.303tlogP02P0−Pt
=2.303300 slog0.302×0.30−0.50
=2.303300 slog0.300.60−0.50
=2.303300 slog0.300.10
=2.303300 slog3
=2.303300 s×0.4771
=1.099300 s
=0.0036 s−1
=3.6×10−3 s−1
© examsiri.com
Go to Question: