CBSE Class 12 Chemistry 2014 Delhi Set 1 Solved Paper

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Question : 22 of 30
 
Marks: +1, -0
The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume: SO2Cl2(g) → SO2(g)+Cl2(g)
 Experiment  Time /s−1  Total pressure/atm
 1  0  0.4
 2  100  0.7
Calculate the rate constant.
(Given: long 4=0.6021,log2=0.3010 )
Solution:
The given reaction is,
SO2Cl2(g) → SO2(g)+Cl2(g)
Pi=0.4atm,P=0.7atm,t=100s
Thus, according to the integrated rate law for gas phase
K=2.303t×log10Pi2Pi−P
K=2.303×10−2×log100.40.1
K=2.303×10−2×log10(4)
K=2.303×10−2×0.6021
K=1.3866×10−2 s−1
Thus, the rate constant for the above reaction is 1.3866×10−2 s−1.
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