CBSE Class 10 Science 2022 Outside Delhi Term II Set 3

Question : 3 of 7

Marks: +1, -0

Consider the carbon compounds having following molecular formula:(i)

{\C}_2 {\H}_2

(ii)

{\C}_2 {\H}_6

(iii)

{\C}_3 {\H}_7 {\OH}

(iv)

{\C}_2 {\H}_5 {\COOH}

(v)

{\CH}_3 {\CHO}

(a) Identify which one of the above compounds, is a member of aldehyde series.
(b) Write the general formula of the series to which compound

{\C}_2 {\H}_2

belongs.
(c) Which one of the above compounds has triple bonds between carbon - carbon atoms?
(d) Write the molecular formula of the first member of the homologous series to which the compound

{\C}_3 {\H}_7 {\OH}

belongs.

Solution:

(a) Acetaldehyde

( {\CH}_3 {\CHO})

is a member of aldehyde series.
(b) Ethyne

( {\C}_2 {\H}_2)

is the first member of the alkyne family, with two carbon atoms connected by a triple bond. Alkynes comprise a series of carbon and hydrogenbased compounds that contain at least one triple bond. This group of compounds is a homologous series with the general molecular formula of

{\C}_n {\H}_{2 n-2^{'}}

, where

n

equals to any integer greater than one.
(c) Ethyne

( {\C}_2 {\H}_2)

have two carbon atoms connected by a triple bond.
(d)

{\C}_3 {\H}_7 {\OH}

belongs to the homologous series with general formula of

{\C}_n {\H}_{(2 n+1)} {\OH}

The first member of this series is

{\C}_1 {\H}_{(2(1)+1)} {\OH}= {\CH}_3 {\OH} \;\text " methanol. "\;

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