Given : $\mathit{u}=-30\mathrm{cm},\mathit{f}=15\mathrm{cm}$.
We know that, $\frac{1}{\mathit{v}}+\frac{1}{\mathit{u}}=\frac{1}{\mathit{f}}$
$\frac{1}{\mathit{v}}=\frac{1}{15}+\frac{1}{30}=\frac{2+1}{30}=\frac{3}{30}$
$\mathit{v}=10\mathrm{cm}$
Characteristics of image :
(i) Image formed is erect.
(ii) Image formed is small in size.
(iii) Image formed is virtual.
(iv) Image is formed at a distance of $10\mathrm{cm}$ behind the mirror between focus and pole.